2n^2-8n-2040=0

Solution for 2n^2-8n-2040=0 equation:

2n^2-8n-2040=0

a = 2; b = -8; c = -2040;
Δ = b2-4ac
Δ = -82-4·2·(-2040)
Δ = 16384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16384}=128$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-128}{2*2}=\frac{-120}{4}
=-30
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+128}{2*2}=\frac{136}{4}
=34
$